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Standard XII

Chemistry

Abnormal Colligative Properties

The molar hea...

Question

The molar heat capacity of water of constant pressure is $75 J K^{- 1} m o l^{- 1} .$ When $1 k J$ of heat is supplied to $100 g$ of water, which is free to expand, the increase in temperature of water is

6.6 K

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1.2 K

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2.4 K

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4.8 K

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Solution

The correct option is C 2.4 K
$100 g$ of water
$n = \frac{100}{18} = 5.5 m o l e s$
$d H = n e p d T$
$1 K J = 5.5 \times 75 J k^{- 1} m o l^{- 1} d T$
$\frac{10^{3}}{5.5 \times 75} = d T$
$\frac{1000 \times 10}{55 \times 75} k = d T = 2.42 k$

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The molar heat capacity of water of constant pressure is 75JK−1mol−1. When 1kJ of heat is supplied to 100g of water, which is free to expand, the increase in temperature of water is

The correct option is C 2.4 K100g of watern=10018=5.5molesdH=nepdT1KJ=5.5×75Jk−1mol−1dT1035.5×75=dT1000×1055×75k=dT=2.42k

The molar heat capacity of water of constant pressure is $75 J K^{- 1} m o l^{- 1} .$ When $1 k J$ of heat is supplied to $100 g$ of water, which is free to expand, the increase in temperature of water is

The correct option is C 2.4 K
$100 g$ of water
$n = \frac{100}{18} = 5.5 m o l e s$
$d H = n e p d T$
$1 K J = 5.5 \times 75 J k^{- 1} m o l^{- 1} d T$
$\frac{10^{3}}{5.5 \times 75} = d T$
$\frac{1000 \times 10}{55 \times 75} k = d T = 2.42 k$