The molarity of $20 % . (\frac{V}{V}) H_{2} S O_{4}$ is 2.55M, the density of the sulphuric acid solution which was put in is

125 g . C m^{- 3}

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12.5 g . C m^{- 3}

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1.25 g . C m^{- 3}

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0.125 g . C m^{- 3}

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Solution

The correct option is C $1.25 g . C m^{- 3}$
$d = \frac{M \times G M W}{10 \times %} = \frac{2.55 \times 98}{10 \times 20} = 1.25 g . c m^{- 3}$

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