The molarity of a solution made by mixing 50 ml of conc. $H_{2} {S O}_{4} (36 N)$ with 50 ml of water is

36 M

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18 M

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9 M

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6 M

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Solution

The correct option is C 9 M
$Concentrated H_{2} S O_{4} 36 N i s 18 M sulphuric acid$

$We can use the formula:$

$M_{1} V_{1} = M_{2} V_{2}$

$W h e r e$

$M_{1} = i n i t i a l m o l a r i t y$
$V_{1} = i n i t i a l v o l u m e$
$M_{2} = f i n a l m o l a r i t y$
$V_{2} = f i n a l v o l u m e$

$18 \times 50 = M_{2} \times (50 + 50)$

$900 = 100 \times M_{2}$

$M_{2} = 9$

$The molarity of the solution is 9M .$

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