Question

The molecular formula of an organic compound is $C_4{H}_9$. The volume of $N_2$ that will be given by 0.2 g of the above compound at STP is(ml):

• A. 31.5
• B. 50
• C. 63
• D. 93

Answer 1

Answer: (A)

31.5

Moles of $N_2$ present in the compound= $\frac{14}{28}=0.5$

Molecular weight of $C_4{H}_{9}N=71$

$\therefore 71g$ compound contains $0.5$ mol $N_2$

$\therefore 0.2g$ compound contains $\frac{0.5\times 0.2}{71}=1.408\times {10}^{-3}$ moles of $N_2$

Volume of $1mol$ $N_2=22400ml$

$\therefore$ Volume of $N_2$ given by the compound= $22400\times 1.408\times {10}^{-3}=31.5ml$