The molecular mass of sodium hydroxide is 40. If 1 litre of sodium hydroxide solution is prepared by dissolving 12 g of it then the molarity of the solution will be:
0.3 M
Mass of sodium hydroxide (NaOH) taken = 12 g
Molar mass of NaOH = 40 g.
Number of moles of NaOH = 1240=0.3
Volume of solution = 1 l
∴ Concentration =0.31=0.3M