Question

The molecular weight of a gas is 44. The volume occupied by 2.2 grams of the gas at $STP$ is:

• A. 1.12 $L$
• B. 1.4 $L$
• C. 2.24 $L$
• D. 5.6 $L$

Answer 1

Answer: (A)

1.12 $L$

2.2 gm of gas corresponds to $\frac{2.2}{44}=0.05$ mole.

1 mole occupies 22.4 $L$ at $STP$.

Hence, 0.05 mole will occupy $0.05\times 22.4L=1.12L$

Hence, the correct answer is option $\text{A}$.