The molecules having the same hybridization, shape and number of lone pairs of electrons are :

S e F_{4}, X e O_{2} F_{2}

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{S F}_{4}, X e F_{2}

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X e O F_{4}, T e F_{4}

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S e {C l}_{4}, X e F_{4}

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Solution

The correct option is A $S e F_{4}, X e O_{2} F_{2}$
$S e F_{4}$ and $X e O_{2} F_{2}$ are both ${s p}^{3} d$ hybridized, trigonal bipyramidal and see-saw shaped with 1 lone pair of electrons each.

${S F}_{4}$ has 1 lone pair, $X e F_{2}$ has 3 lone pairs.

$X e O F_{4}$ is square pyramidal with 1 lone pair, $T e F_{4}$ is see-saw shaped with 1 lone pair.

$S e {C l}_{4}$ has see-saw shape with 1 lone pair, $X e F_{4}$ has a planar shape with 2 lone pairs.

Hence, option A is correct.

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