The moment of a force of $10 N$ about a fixed point on is $5 N m$ . Calculate the distance of the point $O$ from the line of action of the force.

Open in App

Solution

It is known tha
Moment of force = force x perpendicular distance of force from point O
Moment of force $= F \times r$
putting values:
$5 = 10 \times r$
$R = 5 / 10 = 0.5 m$

Suggest Corrections

Similar questions

The moment of force due to a force of $10 N$ acting about a point O is $5 N m$ . Calculate the distance of the point of application of the force from the point O.

The torque due to a force of $10 N$ acting tangentially about a point P is $5 N m$ . Calculate the distance of the point of application of the force from the point P.

Q. If the moment of force of

8 N

about a point P is

4 N m

, calculate the distance of the point of application of the force from the point P.

Q. The moment of force of 8 N about a point P is 4 N m. Calculate the distance of point of application of the force from the point P.

Q. The moment of force of

5 N

about a point

P

20 N m

. Calculate the distance of point of application of the from the point

P

Join BYJU'S Learning Program

The moment of a force of 10 N about a fixed point on is 5 N m. Calculate the distance of the point O from the line of action of the force.

It is known thaMoment of force = force x perpendicular distance of force from point OMoment of force=F×rputting values:5=10×rR=5/10=0.5m

The moment of a force of $10 N$ about a fixed point on is $5 N m$ . Calculate the distance of the point $O$ from the line of action of the force.

It is known tha
Moment of force = force x perpendicular distance of force from point O
Moment of force $= F \times r$
putting values:
$5 = 10 \times r$
$R = 5 / 10 = 0.5 m$