Question

The moment of force of $5N$ about a point $P$ is $20Nm$. Calculate the distance of point of application of the from the point $P$.

• A. $3m$
• B. $0.6m$
• C. $4m$
• D. $10m$

Answer 1

Answer: (C)

$4m$

Given : $F=5$ N

Moment of force (or torque ) $\tau =20$ $Nm$

Let the distance of point of application of force from point P be $d$.

$\therefore$ $\tau =Fd$

OR $20=5\times d$ $⟹d=4$ $m$