Question

The momentum ( in Kg-m/s) of an electron having wavelength 2$A^0$ $(h=6.62\times {10}^{-34}Js.)$

• A. $3.3125\times {10}^{-24}$
• B. $4.24\times {10}^{-23}$
• C. $1.82\times {10}^{-29}$
• D. $1.28\times {10}^{-12}$

Answer 1

The correct option is A $3.3125\times {10}^{-24}$

The relationship between de Broglie wavelength $\left(\lambda \right)$ and the momentum (p) of a photon is given by:
$\lambda =\frac{h}{p}$.
Using this, the momentum of an electron having wavelength $2\mathring{A}$ is $3.3125\times {10}^{-24}$kg-m/s.
So, the answer is option (A).