The monkey B shown in figure is holding on to the tail of the monkey of A which is climbing up a rope. the masses of the monkeys A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail, what force should it apply on the rope in order to carry the monkey B with it ? Take g= $10 m / s^{2}$

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Solution

Suppose $A$ move upward with acceleration $a$ , such that in the tail of $A$ maximum tension $30 N$ produced.
$T - 5 g - 30 - 5 a = 0$ ... (i) $30 - 2 g - 2 a = 0$ ... (ii)
$\Rightarrow T = 50 + 30 + (5 \times 5) = 105 N$ (max) $\Rightarrow 30 - 20 - 2 a = 0 \Rightarrow a = 5 m / s^{2}$
So; A can apply a maximum force of $105 N$ in the rope to carry the monkey $B$ with it.
For minimum force there is no acceleration of monkey $^{'} A^{'}$ and $B \Rightarrow a = 0$
Now equation (ii) is $T_{1} - 2 g = 0 \Rightarrow T_{1} = 20 N$
Equation (i) is $T - 5 g - 20 = 0$ [As $T_{1} = 20 N$ ]
$\Rightarrow T = 5 g + 20 = 50 + 20 = 70 N$
$∴$ The monkey A should apply force between $70 N$ and $105 N$ to carry the monkey $B$ with it.

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Q. The monkey B shown in figure is holding on to the tail of the monkey A which is climbing up a rope.The masses of the monkey A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail , what force it should apply on the rope in order to carry the monkey B with it ? Take

g = 10 m / s^{2}

Q. The monkey

B

, shown in the following figure, is holding on to the tail of monkey

A

that is climbing up a rope. The masses of monkeys

A

and

B

are

5 kg

and

2 kg

respectively. If

A

can tolerate a tension of

30 N

in its tail, what force should it apply on the rope in order to carry monkey

B

with it? (Take

g = 10 {m/s}^{2}

)

The monkey B shown in figure is holding on to the tail of the monkey A which is climbing up a rope. The masses of the monkeys A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail, what force should it apply on the rope in order to carry the monkey B with it ? Take g = 10 $m / s^{2}$ .