The monomer of the given polymer is:

C H_{2} = C (C H_{3})_{2}

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{({C H}_{3})}_{2} C = C {({C H}_{3})}_{2}

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{C H}_{3} C H = C H {C H}_{3}

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{C H}_{3} C H = {C H}_{2}

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Solution

The correct option is A $C H_{2} = C (C H_{3})_{2}$
In the presence of acids, isobutene forms isobutyl carbenium ion. Subsequent deprotonation of the isobutyl carbenium ion results in a mixture of the two products (a) and (b). Further oligomerization results in the formation of another cationic intermediate, which then keeps elongating the polymer chain. Termination of the reaction occurs by deprotonation or addition of a negatively charged Lewis base. This is explained in the diagram.

Hence, the correct option is A.

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Similar questions

C H_{3} C H = C H_{2}

C H_{3} C H = C H C H_{2} C H_{3}

C H_{3} C H = C H C H_{3}

C H_{3} C H = C H C H_{3}

C H_{3} C H_{2} C H = C H_{2}

How many primary, secondary, tertiary and quaternary carbons are present in the following hydrocarbon

$C H_{3} - C H (C H_{3}) - C (C H_{3})_{2} - C H_{2} - C H (C H_{3}) - C H_{2} - C H_{3}$

C H_{3} C H = C (C H_{3})_{2} + H C l \to

C_{6} H_{5} \oplus C H_{2}

C_{6} H_{5} C H_{2} \oplus C H_{2}

C_{6} H_{5} \oplus C H C H_{3}

C_{6} H_{5} \oplus C (C H_{3})_{2}

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