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Question

The most general solutions of the equation secx1=(21)tanx are given by


A

nπ + π/8

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B

2nπ, 2nπ + π/4

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C

2nπ

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D

(2n+1) π

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Solution

The correct option is B

2nπ, 2nπ + π/4


Let 'C' be the point where the cloud is located.

Let 'A' be the point 200 m above the lake.

In ΔABC

tan 30=hx

13=hx

x=h3.....(i)

In ΔABE

tan 60=400+hx

3=400+hh3

3h = 400 + h

2h = 400

h = 200 m

the height of cloud above the lake = 200 + 20

= 400 m


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