You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Faraday's First Law

The most stab...

Question

The most stable oxidation state of $M n$ is:

M n^{4 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M n^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n^{6 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $M n^{4 +}$
Out of th given reactions, higher the value of $E^{o}$ , more favourable is the reaction.
Hence, reaction (ii) is the most favourable where $M n^{4 +}$ is being formed. Hence, $M n^{4 +}$ is the most stable oxidation state of $M n$ .

Suggest Corrections

Similar questions

E_{R P}^{o}

and their respective half reactions for some changes are given below:

(a)

M n O_{4}^{-} (a q) + 8 H^{+} + 5 e \to M n^{2 +} (a q) + 4 H_{2} O (l); E^{o} = + 1.52 V

(b)

M n O_{4}^{2 -} (a q) + 4 H^{+} + 2 e \to M n O_{2} (s) + 2 H_{2} O (l); E^{o} = + 2.26 V

(c)

2 M n O_{4}^{-} (a q) + 2 e \to 2 M n O_{4}^{2 -} (a q); E^{o} = + 0.56 V

(acid med.)
(d)

M n^{3 +} + e \to M n^{2 +}; E^{o} = + 1.51 V

(acid med.)
(e)

M n^{4 +} + e \to M n^{3 +}; E^{o} = 0.95 V

(acid med.)

The most stable oxidation state of Mn is :

Q. Equivalent weight

{M n}^{3 +}

in the following reaction is (

M n = 55

) :

{M n}^{3 +} ⟶ {M n}^{2 +} + M n O_{2}

Q. Write balanced chemical equations for action of potassium permanganate on:
(a) Hydrogen
(b) Warm conc. sulphuric acid
Explain why

M n^{2 +}

ion is more stable than

M n^{3 +}

?
(Given:

M n \to Z = 25)

Q. Explain why:

M n^{2 +}

is more stable than

F e^{2 +}

towards oxidation to +3 state.
(At. no. of Mn = 25, Fe = 26)

The standard redox potential for reactions Mn²⁺+2e -----> Mn and Mn³⁺+1e -----> Mn²⁺ are 2.36 and 1.51V respectively . What is the redox potential for the reaction Mn³⁺+3e------> Mn ?

Join BYJU'S Learning Program

The most stable oxidation state of Mn is:

The correct option is A Mn4+Out of th given reactions, higher the value of Eo, more favourable is the reaction.Hence, reaction (ii) is the most favourable where Mn4+ is being formed. Hence, Mn4+ is the most stable oxidation state of Mn .

The most stable oxidation state of $M n$ is:

The correct option is A $M n^{4 +}$
Out of th given reactions, higher the value of $E^{o}$ , more favourable is the reaction.
Hence, reaction (ii) is the most favourable where $M n^{4 +}$ is being formed. Hence, $M n^{4 +}$ is the most stable oxidation state of $M n$ .