The most suitable reagent for the given conversion is :

$ \stackrel{\eta}{\longrightarrow} $

H_{2} / P d

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N a B H_{4}

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B_{2} H_{6}

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L i A l H_{4}

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Solution

The correct option is C $B_{2} H_{6}$
Diborane $(B_{2} H_{6})$ reduces only carboxlic group $(C O O H)$ in presence of ketone or ester groups.
$L i A l H_{4}$ will reduce amide, ketone, nitrile and carboxylic acid group.
$N a B H_{4}$ will reduce only ketone group.
$P d / H_{2}$ will reduce only nitrile.

Hence, option (a) is the correct answer.

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The most suitable reagent for the following conversion is:

R C H_{2} O H \to R C H O

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