The motion of a particle executing SHM is given by x-0-01sin 100-t-0-05- where x is in metre and t in second- The time period of motionin second is-

The correct option is B 0.02 x=0.01sin 100π(t+0.05) #160; #160; .... (i) Standard equation is x=Asin(ω t+ϕ) #160; #160;.... ...

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Standard XI

Mathematics

Equations involving sinx + cosx and sinx.cosx

The motion of...

Question

The motion of a particle executing SHM is given by $x = 0.01 sin 100 π (t + 0.05)$ , where $x$ is in metre and $t$ in second. The time period of motion(in second) is:

0.01

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0.02

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Solution

The correct option is B $0.02$
$x = 0.01 sin 100 π (t + 0.05)$ .... $(i)$
Standard equation is $x = A sin (ω t + ϕ)$ .... $(i i)$
Comparing Eqs. $(i)$ and $(i i)$ , we get
$ω = 100 π$
$∴ T = \frac{2 π}{ω} = \frac{2 π}{100 π} = \frac{1}{50} s$
$T = 0.02 s$

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The motion of a particle executing SHM is given by x=0.01sin100π(t+0.05), where x is in metre and t in second. The time period of motion(in second) is:

The correct option is B 0.02x=0.01sin100π(t+0.05) ....(i)Standard equation is x=Asin(ωt+ϕ) ....(ii)Comparing Eqs. (i) and (ii), we getω=100π∴T=2πω=2π100π=150sT=0.02s

The motion of a particle executing SHM is given by $x = 0.01 sin 100 π (t + 0.05)$ , where $x$ is in metre and $t$ in second. The time period of motion(in second) is:

The correct option is B $0.02$
$x = 0.01 sin 100 π (t + 0.05)$ .... $(i)$
Standard equation is $x = A sin (ω t + ϕ)$ .... $(i i)$
Comparing Eqs. $(i)$ and $(i i)$ , we get
$ω = 100 π$
$∴ T = \frac{2 π}{ω} = \frac{2 π}{100 π} = \frac{1}{50} s$
$T = 0.02 s$