The multiplicative inverse of $3 - 4 i$

3 + 4 i

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\frac{3 + 4 i}{5}

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\frac{3 - 4 i}{25}

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\frac{3 + 4 i}{25}

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Solution

The correct option is D $\frac{3 + 4 i}{25}$
To find multiplicative inverse of $3 - 4 i$

we have to find a complex number $^{'} z^{'}$ such that $(3 - 4 i) \times z = 1$

$∴ z = \frac{1}{3 - 4 i}$

$= \frac{3 + 4 i}{3^{2} - (4 i)^{2}}$

$= \frac{3 + 4 i}{25}$

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Similar questions

The multiplicative inverse of 3 - 4i is

\frac{3 + 4 i}{4 - 5 i}

\frac{3 + 4 i}{4 - 5 i}

\frac{\sqrt{3 + 4 i} + \sqrt{3 - 4 i}}{\sqrt{3 + 4 i} - \sqrt{3 - 4 i}}

\frac{\sqrt{3 + 4 i} + \sqrt{3 - 4 i}}{\sqrt{3 + 4 i} - \sqrt{3 - 4 i}}

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