The mutual inductance of a pair of coils, each of N turn, be M henry. If a current of i ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt will be

\frac{M i}{t}

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\frac{N M i}{t}

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\frac{M N}{i t}

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\frac{M i}{N t}

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Solution

The correct option is D $\frac{M i}{N t}$
Induced emf = Mutual Inductance $\times \frac{d i}{d t}$
$e = M \frac{d i}{d t}$
In given problem, for N turns,
$e = M \frac{i}{t}$
So, induced emf per turn in the coil is Mi/Nt.

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The mutual inductance of a pair of coils, each of N turn, be M henry. If a current of i ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt will be

The correct option is D MiNtInduced emf = Mutual Inductance ×didte=MdidtIn given problem, for N turns,e=MitSo, induced emf per turn in the coil is Mi/Nt.

The correct option is D $\frac{M i}{N t}$
Induced emf = Mutual Inductance $\times \frac{d i}{d t}$
$e = M \frac{d i}{d t}$
In given problem, for N turns,
$e = M \frac{i}{t}$
So, induced emf per turn in the coil is Mi/Nt.