CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two coils A and B have mutual inductance 2×102 henry. If the current in the primary is i=5sin10πt then maximum value of emf induced in coil B is

A
πvolt
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
π2volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π3volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π4volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C πvolt
Given : Current i=5 sin(10πt)
Mutual inductance L=2×102H=0.02H
Induced emf, E=Mdidt

|E|=M×5(10π)cos(10πt)
|E|max=M×50π=0.02×50π=π volt

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alternating Current Applied to an Inductor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon