The nature of the aqueous solution after Kolbe electrolysis is:

Acidic

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Alkaline

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Neutral

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May be acidic, alkaline or neutral

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Solution

The correct option is B Alkaline
The reaction of Kolbe electrolysis:
$2 R C O O N a + 2 H_{2} O e l e c t r o l y s i s ⟶ R - R + 2 C O_{2} + 2 N a O H + H_{2}$

After completion of reaction solution will be alkaline due to formation of $N a O H$ (strong base).

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