Question

The nature of the precipitate formed when sodium hydroxide reacts with iron (II) sulphate is of

• A. iron (III) hydroxide which is dirty green in colour and insoluble in excess of NaOH.
• B. iron (II) hydroxide which is dirty green in colour and insoluble in excess of NaOH.
• C. sodium sulphate which is yellow in colour and soluble in excess of NaOH.
• D. sodium sulphate which is dirty green in colour and soluble in excess of NaOH.

Answer 1

The correct option is B

iron (II) hydroxide which is dirty green in colour and insoluble in excess of NaOH.

The reaction of sodium hydroxide with iron(II) sulphate is shown below:

$FeS{O}_4+2NaOH$$\to$$N{a}_{2}S{O}_4+Fe\left(OH{)}_2\right(\downarrow )$

The precipitated iron (II) hydroxide is dirty green in colour and is insoluble in excess of NaOH.