The negation of p - q - q - r isA- - p - q -q - rB- - p - q - q - r C- - p - q - q - rD- p - q - q - r

The correct option is C (∼ p ∧∼ q)∨ (∼ q ∧ r)∼ [(p ∨ q)∧ (q ∨∼ r)]≡∼ (p ∨ q)∨∼ (q ∨∼ r) ≡ (∼ p ∧∼ q)∨ (∼ q ∧ r) ...

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Negation

The negation ...

Question

The negation of $(p \lor q) \land (q \lor \sim r)$ is

(\sim p \land \sim q) \lor (q \land \sim r)

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(\sim p \land \sim q) \lor (\sim q \land r)

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(\sim p \land \sim q) \lor (\sim q \land r)

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(p \land q) \lor (\sim q \land \sim r)

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Solution

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Similar questions

Negation of the statement $\sim p \to (q \lor r)$ is

(p \land q) \to (\sim p \lor r)

\sim p \to (q \lor r)

The negation of $q \lor \sim (p \land r)$ is ___.

(p \land q) \to (\sim p \lor r)

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