Question

The normality of mixture obtained by mixing 100 ml of $0.2M{H}_{2}S{O}_4+100ml$ of 0.2 M NaOH is:

• A. 0.2
• B. 0.01
• C. 0.1
• D. 0.03

Answer 1

Answer: (C)

0.1

Given that,

Volume of $H_{2}S{O}_4=100$

Molarity of NaOH = 0.2 M

Milliequivalents of NaOH =$100\times 0.2\times 1=20$

Milliequivalent of $H_{2}S{O}_4=100\times 0.2\times 2=40$

The reaction is:

$H_{2}S{O}_4+NaOH\to NaCl+H_{2}O$

ml. eqv 40 20

before reaction

ml. eqv 20 0 20 20

after reaction

Total volume of solution = 100 ml + 100 ml = 100 ml

Normality of remaining solution $=\frac{milliequivalentsleft}{VolumeofsolutioninL}=\frac{20}{200}=0.1N$

Hence, the answer is option $C$.