Question

The nuclear radius of a nucleus with nucleon number $16$ is $3\times {10}^{-15}m$. Then, the nuclear radius of a nucleus with nucleon number $128$ is :

• A. $3\times {10}^{-15}m$
• B. $1.5\times {10}^{-15}m$
• C. $6\times {10}^{-15}m$
• D. $4.5\times {10}^{-15}m$

Answer 1

The correct option is C $6\times {10}^{-15}m$

$R=R_o{A}^{1/3}$

where, $A$ is the nucleon number

$\frac{R_1}{R_2}=(\frac{A_1}{A_2}{)}^{1/3}$

$\frac{R_2}{3\times {10}^{15}}=(\frac{128}{16}{)}^{1/3}$

$R_2=6\times {10}^{-15}m$