Question

The nucleophilic addition at the carbonyl carbon changes its hybridization fromto

• A. $sp$
• B. $s{p}^2$
• C. $s{p}^3$
• D. $s{p}^{3}d$

Answer 1

Answer: (B), (C)

The correct options are
B $s{p}^2$
C $s{p}^3$

Carbonyl carbons are planar and $s{p}^2$ hybridized. When a nucleophile adds to the carbonyl carbon, its leads to the formation of a tetrahedral intermediate which is $s{p}^3$ hybridized.