The nucleus of element X(A=220) undergoes α−decay. If Q-value of the reaction is 5.5 MeV, then the kinetic energy of α−particle is:
Applying law of conservation of linear momentum and using the energy released
Velocity of α -particle and daughter nucleus is
Therefore, the kinetic energy of α particle
E=220−4220×5.4
E=5.4Mev
Hence, the kinetic energy is 5.4 Mev