The number of $7$ digit number which can be formed using the digits $1, 2, 3, 2, 3, 3, 4$ is

420

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5040

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2550

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840

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Solution

The correct option is A $420$
Given, $1, 2, 3, 2, 3, 3, 4$
Number of seven digit numbers can be arranged by above digits are
2 is repeated twice and 3 is repeated thrice
$\Rightarrow \frac{7!}{2! \times 3!} = 420$
Hence option A is correct

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The number of 7 digit number which can be formed using the digits 1,2,3,2,3,3,4 is

The correct option is A 420Given, 1,2,3,2,3,3,4Number of seven digit numbers can be arranged by above digits are2 is repeated twice and 3 is repeated thrice ⇒7!2!×3!=420Hence option A is correct

The number of $7$ digit number which can be formed using the digits $1, 2, 3, 2, 3, 3, 4$ is

The correct option is A $420$
Given, $1, 2, 3, 2, 3, 3, 4$
Number of seven digit numbers can be arranged by above digits are
2 is repeated twice and 3 is repeated thrice
$\Rightarrow \frac{7!}{2! \times 3!} = 420$
Hence option A is correct