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B
6
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C
8
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D
4
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Solution
The correct option is A \N
In BrF5, there are 5 bond pairs and 1 lone pair on Br atom and hence the hybridization is sp3d2, the geometry and shape are octahedral and square pyramidal respectively. Due to lp-bp repulsions, the bond angles are lower than 90∘(as in octahedral). Hence there are no bond angles with 90∘.