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Question

The number of α and β-particles emitted during the transformation of 90Th232 to 82P208 are respectively

A
4, 2
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B
2, 2
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C
8, 6
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D
6, 4
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Solution

The correct option is D 6, 4
90Th23282P208+x2He4+y1β0
Equating mass no.
232 = 208 + 4x + 0 y or 4x = 24 or x = 6
Equating atomic no.
90=82+2xy or 90=82+2×6y or
Hence 6α and 4β particles will be emitted.

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