Given, y=x2−3x+2x2+3x+2=(x−1)(x−2)(x+1)(x+2), Domain is R−{−1,−2}
limx→−1−y=−∞,limx→−1+y=∞
⇒x=−1 is a vertical asymptote⋯(i)
limx→−2−y=∞,limx→−2+y=−∞
⇒x=−2 is a vertical asymptote⋯(ii)
limx→±∞y=1
⇒y=1 is a horizontal asymptote⋯(iii)
Given curve has no inclined asymptotes
∵{limx→±∞yx}=limx→±∞x2−3x+2x(x2+3x+2)=0
Hence the given function has 3 asymtotes.