The number of atoms in $0.25$ mole of a tetra-atomic gas is:
( $N_{A} =$ Avogadro number)

4 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{A}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 N_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N_{A}$
(C) NA
Because tetratomic means, in 1 molecule of
gas $= 4$ atoms of gas.

no.of mole of atoms $= 4 \times$ no of.mole of molecule
$= 4 \times 0.25$

$= 4 \times \frac{25}{100} = 1 = N A .$

Suggest Corrections

Similar questions

Q. The total number of atoms present in

1

mole of potash alum, in terms of Avogadro number

N_{A}

, is:

[ Potash Alum

= K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O

]

The number of atoms present in one mole of an element is equal to Avogadro's number. Which of the following element contains the greatest number of atoms?

(a) 4 g He

(b) 46 g Na

(d) 12 g He

Q. The number of atoms in

0.1

mole of a triatomic gas is:

(N_{A} = 6.02 \times 10^{23})

Q. The number of atoms in 0.1 mole of a tetra atomic gas is:

G i v e n : (N_{A} = 6.02 \times 10^{23} m o l^{- 1})

Q. The numbers of atoms present in

11.2 L

S O_{2}

at STP is: (Where

N_{A}

is the Avogadro constant)

Join BYJU'S Learning Program

The number of atoms in 0.25 mole of a tetra-atomic gas is: (NA= Avogadro number)

The correct option is C NA(C) NA Because tetratomic means, in 1 molecule of gas =4 atoms of gas.no.of mole of atoms =4× no of.mole of molecule =4×0.25=4×25100=1=NA.

The number of atoms in $0.25$ mole of a tetra-atomic gas is:
( $N_{A} =$ Avogadro number)

The correct option is C $N_{A}$
(C) NA
Because tetratomic means, in 1 molecule of
gas $= 4$ atoms of gas.

no.of mole of atoms $= 4 \times$ no of.mole of molecule
$= 4 \times 0.25$

$= 4 \times \frac{25}{100} = 1 = N A .$