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Question

The number of atoms in 100 g of an FCC crystal with density d=10 g/cm3 and cell edge equal to is equal to

A
4×1025
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B
3×1025
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C
2×1025
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D
1×1025
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Solution

The correct option is A 4×1025

M=ρ×a3×N0×1030z=10×(100)3×(6.02×1023)×10304=15.05
No. of atoms in 100 g =6.02×102315.05×100=4×1025.


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