The number of atoms of the $H e$ in $104 a m u$ is:

3.1 \times 10^{25}

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6.2 \times 10^{25}

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26

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206

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Solution

The correct option is B $26$
Since the mass of one atom of He = 4 a.m.u
Therefore the number of atoms of the He in 104 amu is, $\frac{104}{4} = 26$ .

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