Question

The number of atoms present in $16$ g of oxygen is :

• A. $6.02\times {10}^{11.5}$
• B. $3.01\times {10}^{23}$
• C. $3.01\times {10}^{11.5}$
• D. $6.02\times {10}^{23}$

Answer 1

The correct option is D $6.02\times {10}^{23}$

Moles of $O_2=\frac{16}{32}=\frac{1}{2}$
Number of molecules = $\frac{1}{2}\times N_A$
Number of atoms = $2\times \frac{1}{2}\times N_A$