The number of atoms present in 4.25 grams of NH3 is pproximately
1 X 1023
1.5 X 1023
2 X 1023 NH3
6.02 X 1023
4.2517 × 4 × 6.023 × 1023 = 6.023 × 1023
The number of atoms present in 4.25 grams of NH3 is approximately
The number of molecules present in 4.25 grams of NH3 is approximately:
The number of atoms present in 4.25 grams of NH3 is approximately________.
The number of atoms present in 4.25 g of NH3 is approximately.
a) 1×1023
b) 1.5×1023
c) 0.25×1023
d) 6.02×1023
THe number of molecules in 4.25 g of ammonia is: (a) 1.0×1023 (b) 1.5×1023 (c) 2.0×1023 (d) 3.5×1023