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Question

The number of atoms present in 4.25 grams of NH3 is pproximately


A

1 X 1023

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B

1.5 X 1023

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C

2 X 1023 NH3

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D

6.02 X 1023

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Solution

The correct option is D

6.02 X 1023


4.2517 × 4 × 6.023 × 1023 = 6.023 × 1023


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