The number of boys and girls are equal in a class. On a day when eight boys did not attend, the number of girls was double the number of boys in this class. What is the actual number of boys and girls?
Let the number of boys in the class be x
The number of boys and girls are equal. So, the number of girls in the class is also x.
The number of boys who did not attend the class = 8
∴ Number of boys who attended the class = x − 8
Number of girls in the class = 2 × (x − 8) = 2x − 16
Algebraic form of the problem is:
2x − 16 = x
Subtracting x from both the sides:
⇒ 2x − 16 − x = x − x
⇒ x − 16 = 0
Adding 16 to both the sides:
⇒ x − 16 + 16 = 0 + 16
⇒ x = 16
Therefore, the actual number of boys and girls in the class is 16.