Question

The number of $C{l}^{-}$ and $C{a}^{2+}$ ions in $222$g of $CaC{l}_2$ is:

• A. $4N_A,2N_A$
• B. $2N_A,4N_A$
• C. $1N_A,2N_A$
• D. $2N_A,1N_A$

Answer 1

The correct option is A $4N_A,2N_A$

$222$g of $CaC{l}_2$ is equal to $2$ moles of $CaC{l}_2$.

Therefore, it has $2$ moles of $C{a}^{2+}$ and $4$ moles of $C{l}^{-}$.

So, no. of atoms of $C{a}^{2+}$ and $C{l}^{-}$ are $2N_A$ and $4N_A$ respectively.