The number of degrees of freedom in a planar mechanism having n links and j simple hinge joints is
A
3(n−3)−2j
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B
3(n−1)−2j
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C
3n−2j
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D
2j−3n+4
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Solution
The correct option is B3(n−1)−2j The relation between the no.of links 'n', lower pair 'j' and higher pair 'h' gives a degree of freedom. For a planar mechanism. F=3(n−1)−2j−h
Here, no higher pair, so, h = 0 F=3(n−1)−2j