The number of diagonals that can be drawn in a hexagon is

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Solution

A hexagon has $6$ sides. We obtain the diagonals by joining the vertices in pairs.
Total number of sides and diagonals $=^{6} C_{2} = \frac{6 \times 5}{2 \times 1} = 5 \times 3 = 15$
This includes its $6$ sides also.

Hence, the number of diagonals is $15 - 6 = 9.$

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Polygons

Standard VIII Mathematics

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The number of diagonals that can be drawn in a hexagon is

A hexagon has 6 sides. We obtain the diagonals by joining the vertices in pairs. Total number of sides and diagonals = 6C2=6×52×1=5×3=15 This includes its 6 sides also. Hence, the number of diagonals is 15−6=9.

A hexagon has $6$ sides. We obtain the diagonals by joining the vertices in pairs.
Total number of sides and diagonals $=^{6} C_{2} = \frac{6 \times 5}{2 \times 1} = 5 \times 3 = 15$
This includes its $6$ sides also.

Hence, the number of diagonals is $15 - 6 = 9.$