The number of diagonals that can be drawn in an `n' sided polygon is 6 less than the number of diagonals that can be drawn in an (n + 1) sided polygon. The value of `n' is -

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Solution

The correct option is B
7

$\frac{(n + 1) (n - 2)}{2}$ = $\frac{n (n - 3)}{2}$ + 6

n = 7

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The number of diagonals that can be drawn in an `n' sided polygon is 6 less than the number of diagonals that can be drawn in an (n + 1) sided polygon. The value of `n' is -

The correct option is B 7 (n+1)(n−2)2= n(n−3)2 + 6 n = 7

The correct option is B
7

$\frac{(n + 1) (n - 2)}{2}$ = $\frac{n (n - 3)}{2}$ + 6

n = 7