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Question

The number of dissimilar terms in the expansion of (1−3x+3x2−x3)20 is:

A
60
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B
30
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C
61
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D
20
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Solution

The correct option is C 61
(13x+3x2x3)20=[(1x)3]20=(1x)60
Therefore number of dissimilar terms in the expansion of (13x+3x2x3)20 is 61.

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