Question

The number of distinct terms in $(a+b+c+d+e{)}^3$ is

• A. $35$
• B. $38$
• C. $42$
• D. $45$

Answer 1

The correct option is A $35$

$(a+b+c+d+e{)}^3$

Number of terms of non integral solution $a+b+c+d+e$

${}^{3+5-1}{C}_{5-1}{=}^7{C}_4=\frac{71}{4131}=\frac{7\times 6\times 5\times 4}{3\times 2\times 4}=7\times 5=35$

Answer A