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Question

The number of distinct terms in the expansion of (x+1x+x2+1x2)15 is/are (with respect to different power of x)

A
255
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B
61
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C
127
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D
none of these
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Solution

The correct option is C 61
We have to expand (x+1x+x2+1x2)15
The Highest power of x in the expansion is 2×15=30
The least power of x in the expansion is 2×(15)=30
The expansion of given expression covers all powers of x between them
Therefore number of distinct terms in the expansion is 30+30+1=61

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