Question

The number of divisors of $240$ in the form $4n+2$ ($n\ge 0$) is equal to

• A. $4$
• B. $8$
• C. $10$
• D. $3$

Answer 1

The correct option is A $4$

$240=2^4{.3}^1{.5}^1$
Divisors in the form of $4n+2$ can be written as $=2\left(3^a\right)\left(5^b\right)$.
$a$ and $b$ both can take 2 values each (0,1).
Hence, total divisors $=1\times 2\times 2=4$.