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Question

The number of electron pairs (ep) in ClF3 is .

A
7
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B
6
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C
5
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Solution

The correct option is C 5

The formula for electron pairs is

ep = (V+L+AC)2
Where V = number of valance electrons of central, L = number of Ligands;
A = Anionic charge, Cationic charge

In ClF3,

The central atom is Cl.

Valance electrons in chlorine is 7

Number of Ligands = 3

Therefore,

ep = (7+3+00)2

ep = 102

ep = 5

The number of electron pairs in ClF3 is 5


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