The number of electrons involved in the reduction of $C r_{2} O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
3

In this reaction three electrons are required for the reduction of $C r_{2} O_{7}^{2 -}$ into $C r^{3 +}$

Suggest Corrections

Similar questions

The number of electrons involved in the reduction of $C r_{2} O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

The number of electrons required to reduce chromium completely in Cr $_{2}$ O $_{7}$ $^{2 -}$ to Cr $^{3 +}$ in acidic medium, is

m o l e s

1 m o l e

{C r_{2} O_{7}}^{2 -}

C r^{3 +}

C r_{2} O_{7}^{2 -} + F e^{2 +} + C_{2} O_{4}^{2 -} \to C r^{3 +} + F e^{3 +} + C O_{2}

Join BYJU'S Learning Program