The number of electrons required to balance the following equation are
$N O_{3}^{-} + 4 H^{+} + e^{-} ⟶ 2 H_{2} O + N O$

5

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4

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3

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2

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Solution

The correct option is C $3$
The given reaction is a redox reaction since here the oxidation state of $N$ in $N O_{3}^{-}$ is $+ 5$ and in $N O$ the oxidation state of $N$ is $+ 2$ . Since oxidation state of $N$ is changing by 3 units, thus the number of electrons required to balance the equation is $3$ .

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