Question

The number of electrons with azimuthal quantum number $l=1$ and $l=2$ for Cr in ground state respectively are:

• A. 18, 5
• B. 16, 4
• C. 12, 4
• D. 16, 3
• E. 12, 5

Answer 1

The correct option is E 12, 5

Electronic configuration of
${}_{24}Cr=1s^2,2s^2,2p^6,3s^2,3p^6,4s^1,3d^5$
Given, azimuthal quantum number $\left(l\right)=1\Rightarrow$ p-orbital
azimuthal quantum number $\left(l\right)=2\Rightarrow d-orbital$. So, number of elections in p = 12 and number of electrons in d - orbital = 5.