Question

The number of electrons with the azimuthal quantum number e = 1 and 2 for ${24}_{Cr}$ in ground state are :

• A. 16 and 5
• B. 12 and 5
• C. 16 and 4
• D. 12 and 4

Answer 1

The correct option is B 12 and 5

For l=1 it is p orbital and l=2 it is d orbital. So the electronic config of Cr with at no 24 is${1s}^2{2s}^2{2p}^6{3s}^2{3p}^6{4s}^1{3d}^5$. It is evident from config. that p orbital has $6+6=12$ electrons and d orbital has 5 electrons.