The number of factors (excluding 1 & the expression itself) of the product of a7b4c3def where a,b,c,d,e,f are all prime numbers is
A
634
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B
1872
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C
1278
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D
2078
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Solution
The correct option is D 1278 To find Number of factors of the product a7b4c3def If we have to find the number of factors of the product =xaybzc Then, Number of factors =(a+1)(b+1)(c+1)−2 Therefore, Number of factors of the product a7b4c3def =(7+1)(4+1)(3+1)(1+1)(1+1)(1+1)−2 =1280−2 =1278 Hence, Option C is correct.